Tcl program to find out unique/odd elements using XOR
Write a Tcl program to find out unique/odd elements from the list 1,3,5,7,7,5,3,1,9.
Input : 1,3,5,7,7,5,3,1,9
output : 9
While there are multiple ways to achieve this, as a VLSI engineer, we'll leverage the XOR operation. XOR (exclusive OR) results in 1 when two inputs are different and 0 when they are equal. In our program, every number appears twice except for 9. Therefore, by XOR-ing all elements in the list, the result will be 9, the unique/odd element.
Below is Tcl Program:
# Define the list
set lst [list 1 3 5 3 1 5 9]
# Initialize a variable to store the result
set result 0
# iterate through the list and XOR all elements
foreach num $lst {
set result [expr {$result ^ $num}]
}
# The 'result' variable now contains the odd element
puts "The odd element in the list is: $result"
"This works well if we have a single unique element, but if there are two or more unique elements, a little extra effort is needed to code that. Please share your thoughts in the comments."
Comments
Post a Comment